Soal Subnetting

1. e. 255.255.255.128
default sub. mask : 11111111.11111111.00000000.00000000
25 subnet : 11111111.11111111.11111111.10000000

2. d. Address - 192.168.1.82
Gateway - 192.168.1.65
/27 = 11111111.11111111.11111111.11100000
255 . 255 . 255 . 224
subnet masknya adalah : 255.255.255.224
Blok subnetnya = 256 – 224 = 32
Net ID Range Broadcast
192.168.1.0 192.168.1.1 – 192.168.1.30 192.168.1.31
…………… …………………………… ……………
192.169.1.64 192.168.1.65-192.168.1.94 192.168.1.95

3. e. 172.31.192.160
IP : 172.31.192.166
Netmask : 255.255.255.248
Subnet untuk IP tersebut ?
Jawab :
Block subnet = 256 – 248 = 8
Maka, 172.31.192.8
172.31.192.16
172.31.192.24
172.31.192.32
----------------
172.31.192.160
------------------

4. d. 255.255.0.0
e. 255.255.252.0

5. d. 172.16.128.0 and 255.255.224.0
jumlah host dari 172.16.128.1 to 172.16.159.254 adalah 8190 host
2n - 2 = yang hasilnya mendekati 8190 adalah 213 = 8192 – 2 = 8190
Karena jumlah bit “0” adalah 13 maka 11111111.11111111.11100000.00000000
Jadi subnetmasknya adalah 255.255.244.0

6. c. broadcast address

7. c. 30 networks / 6 hosts
/29 = 11111111.11111111.11111111.11111000
Subnet masknya = 255.255.255.248
Block subnet = 256 – 248 = 8
Host = 23-2 = 6
Subnet = 25-2 = 30

8. c. 30
255.255.255.224 = / 27
1111111.1111111.1111111.11100000
Maka, host = 25 – 2 = 30

9. c. 255.255.255.224
Yang mendekati 27 dan tidak melebihi jauh yaitu 24, dan host dihitung dari kanan kekiri
11111111.11111111.11111111.11100000
Subnetnya 255.255.255.224

10. c. 255.255.255.240
Yang mendekati 14 dan tidak melebihi jauh yaitu 23 , dan host dihitung dari kanan kekiri…
11111111.11111111.11111111.11110000
Subnetnya 255.255.255.240

11. d. 255.255.255.0
2^7=128
11111111 11111111 11111111 00000000
255 255 255 0

12. c. 172.32.0.0
172.32.65.13 = 10101100.00100000.01000001.00001101
255.255.0.0 = 11111111.11111111.00000000.00000000
10101100.00100000.00000000.00000000
172 . 32 . 0 . 0

13. c. 172.16.208.0
/22 = 11111111.11111111.11111100.00000000 = 255.255.252.0
172.16.210.0 = 10101100.00010000.11010010.00000000
255.255.252.0 = 11111111.11111111.11111100.00000000
10101100.00010000.11010000.00000000
172 . 16 . 208 . 0

14. c. 115.64.6.255
d. 115.64.3.255
e. 115.64.5.128
/22 = 255.255.252.0
Block subnet 256 – 252 = 4
115.64.4.1 – 115.64.7.255

15. c. 200.10.5.64
/28 = 11111111.11111111.11111111.11110000 = 255.255.255.240
200.10.5.68 = 11001000.00001010.00000101.01000100
255.255.252.0 = 11111111.11111111.11111111.11110000
11001000.00001010.00000101.01000000
200 . 10 . 5 . 64

16. f. 8 subnets, 8190 hosts each
/19 = 11111111 11111111 11100000 00000000
Subnet 2^3=8
Host 2^13=8190

17. b. 255.255.255.128
Subnet 2^9=(>500)
Host 2^7=(>100)

11111111 11111111 11111111 10000000
255 255 255 128

Subnetnya 255.255.255.128

18. c. 172.16.64.0
/21 = 11111111.11111111.11111000.00000000 = 255.255.248.0
172.16.66.0 = 10101100.00010000.01000010.00000000
255.255.248.0 = 11111111.11111111.11111000.00000000
10101100.00010000.01000000.00000000
172 . 16 . 64 . 0

19. b. 255.255.254.0
2^6<100<2^7 dan subnet dihitung dari kiri kekanan
11111111 11111111 11111110 00000000
255 255 254 0
Subnetnya 255.255.254.0

20. c. 192.168.19.26 255.255.255.248
/ 29 = 11111111.11111111.11111111.11111000 =
255 . 255 . 255 . 248
Blok subnet = 256 – 248 = 8

Net Id Range Broadcast
192.168.19.0 192.168.19.1 - 192.168.19.6 192.168.19.7
192.168.19.8 192.168.19.9 - 192.168.19.14 192.168.19.15
192.168.19.16 192.168.19.17 - 192.168.19.22 192.168.19.23
192.168.19.24 192.168.19.25 - 192.168.19.30 192.168.19.31

21. b. 255.255.255.128
e. 255.255.255.192
2^8<300<2^9 karena subnet dihitung dari kiri kekanan…
11111111.11111111.11111111.10000000


Subnetnya 255.255.255.128

2^5<50<2^6 karena host dihitung dari kanan kekiri…
11111111.11111111.11111111.11000000

22. a. 172.16.112.0
/25 = 11111111.11111111.11111111.10000000
255 .255 .255 .128
172.16.112.1 = 10101100.00010000.01110000.00000001
255.255.255.128 = 11111111.11111111.11111111.10000000
10101100.00010000.01110000.00000000
172 . 16 . 112 . 0

23. d. 255.255.252.0
Jumlah Host Keseluruhan= 3350
Host = 2^12 – 2 = 4094
Maka netmask yang sesuai adalah :

11111111 11111111 11110000 00000000
255 255 240 0

24. e. 172.16.18.255 255.255.252.0
/22 = 11111111.11111111.11111100.00000000
= 255 .255 .252 .0
Block subnet = 256 – 252 = 4
172.16.17.0 172.16.17.1 – 172.168.17.2 172.16.17.3
-------------- --------------------------------- ---------------

25. c. 4094
/20 = 11111111.1111111.11110000.00000000
= 255 .255 .240 .0
Host = 212 – 2 = 4094

26. b. 90.10.170.93
c. 143.187.16.56
d. 192.168.15.87
/27 = 255.255.255.224
Kelas C
Subnet 2^3=8
Host 2^5-2=30
Blok subnet = 256 – 224 = 32
32, 64, 96, 128,…..

27. c. 255.255.254.0
Host 2^9-2=510 (>450)

11111111 11111111 11111110 00000000
255 255 254 0

Subnetmasknya 255.255.254.0

28. a. The host subnet mask is incorrect.
d. The default gateway is on a different network than the host.